Bug 35423: Fix substr outside of string warning
To test:
Before applying patch
1. Create an authority record, fill field 400$w with "n"
2. Search for the authority you just created
3. Observe a warning has been logged
"substr outside of string"
4. Apply patch
5. Refresh the search results from step 2
6. Observe no warnings have been logged
Signed-off-by: Harrison Hawkins <harrisonhawkins@catalyst.net.nz>
Signed-off-by: Katrin Fischer <katrin.fischer.83@web.de>
Signed-off-by: Lucas Gass <lucas@bywatersolutions.com>
(cherry picked from commit 3c34d7bf43)
Signed-off-by: Jacob O'Mara <Jacob.omara@openfifth.co.uk>
This commit is contained in:
parent
5f40e97139
commit
12eda3ea41
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@ -1080,7 +1080,7 @@ sub BuildSummary {
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my $type = 'seefrom';
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$type = ( $marc21controlrefs{ substr $field->subfield('w'), 0, 1 } || '' ) if ( $field->subfield('w') );
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if ( $type eq 'notapplicable' ) {
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$type = substr $field->subfield('w'), 2, 1;
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$type = substr $field->subfield('w'), 2, 1 if length( $field->subfield('w') ) > 2;
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$type = 'earlier' if $type && $type ne 'n';
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}
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if ( $type eq 'subfi' ) {
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@ -1103,7 +1103,7 @@ sub BuildSummary {
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my $type = 'seealso';
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$type = ( $marc21controlrefs{ substr $field->subfield('w'), 0, 1 } || '' ) if ( $field->subfield('w') );
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if ( $type eq 'notapplicable' ) {
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$type = substr $field->subfield('w'), 2, 1;
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$type = substr $field->subfield('w'), 2, 1 if length( $field->subfield('w') ) > 2;
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$type = 'earlier' if $type && $type ne 'n';
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}
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if ( $type eq 'subfi' ) {
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